Respuesta :

Answer:

x = -6 ± [tex]i \sqrt{11}[/tex]

Step-by-step explanation:

[tex](x+6)^{2} = -11[/tex]

Taking squareroot we get

x + 6 = ± [tex]\sqrt{-11}[/tex]

x = -6 ± [tex]\sqrt{-11}[/tex]

x = -6 ± [tex]i \sqrt{11}[/tex]

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