Dantron3000
Dantron3000 Dantron3000
  • 24-02-2020
  • Mathematics
contestada

I need help on this problem. It is m FEH=126° and m∠EFG=65·

I need help on this problem It is m FEH126 and mEFG65 class=

Respuesta :

MathPhys
MathPhys MathPhys
  • 24-02-2020

Answer:

∠FEH = 117°

∠EHG = 115°

Step-by-step explanation:

Arc angles add up to 360°.

Arc FEH = 126°, so arc FGH = 234°.

Inscribed angles are half the central angle.

Arc FEH = 126°, so ∠FGH = 63°.

Arc FGH = 234°, so ∠FEH = 117°.

Interior angles of a quadrilateral add up to 360°.

So ∠EHG = 360° − 65° − 63° − 117° = 115°.

Answer Link

Otras preguntas

Who wins, Gigantosaurus or Tyrannosaurus Rex
At approximately what time on the next day does the depth first reach 4 meters? 3:00 am 4:00 am 5:00 pm 10:00 am
. What is the product of √2x • √12500?
can someone please help with This !
how are marine iguana and land iguana are similar? how are they different?​PLS HELP
PLease help me I will give a maybe brainly and a thanks and 3 - 5 stars PLEASE PLEASE
I want to know about the history of The Second Opium War
What did the Waskashan carve? dwellings kayaks canoes totem poles
can 24 divide evenly n2 1240
what but but what how[tex]\small\red{try} [/tex] [tex] \purple{ \rule{500pt}{999999pt}}[/tex][/tex]​