Respuesta :

Answer: Choice D.  [tex]\frac{\ln(28)-5}{3}[/tex]

Work Shown:

[tex]e^{3x+5} = 28\\\\\ln\left(e^{3x+5}\right) = \ln(28)\\\\(3x+5)\ln\left(e\right) = \ln(28)\\\\(3x+5)*1 = \ln(28)\\\\3x+5 = \ln(28)\\\\3x = \ln(28)-5\\\\x = \frac{\ln(28)-5}{3}\\\\[/tex]