shaniarice32 shaniarice32
  • 23-01-2020
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find the slope of the line through points (2,-1) (-3,0)​

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Аноним Аноним
  • 03-02-2020

Answer:

slope = (y2-y1)/(x2-x1)

         = (0 - (-1))/(-3-2)

         = (1)/-5

slope = 1/5 x

y = mx + b

0 = 1/5 (-3) + b

0 = -3/5 + b

3/5 = b

y = 1/5x +3/5

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Yang100
Yang100 Yang100
  • 08-02-2020

Answer:

-1/5

Explanation:

m=(y2-y1)/(x2-x1)

m=(0-(-1))/(-3-2)

m=(0+1)/-5

m=1/-5

m=-1/5

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