Answer:
[tex]\frac {x^{b} - 1}{b}[/tex]
Step-by-step explanation:
[tex]\int_{1}^{x}y^{b-1}dy[/tex]
= [tex][\frac {y^{b}}{b}]_{1}^{x}[/tex]
= [tex]\frac {x^{b} - 1}{b}[/tex]
We know from formula,
[tex]\int x^{n}dx[/tex]
= [tex]\frac {x^{n+1}}{n+1} + c[/tex] [where c is a fixed but otherwise arbitrary
constant]
