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A flowerpot falls from a windowsill 25.0 m above the sidewalk.
How much time does it take for the flowerpot to hit the ground?
If the flowerpot falls for 2.00 s, how high did it drop from?.

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Answer:

2.26 s

19.6 m

Explanation:

Given:

Δy = 25.0 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(25.0 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 2.26 s

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 2.00 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (2.00 s) + ½ (9.8 m/s²) (2.00 s)²

Δy = 19.6 m

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