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  • 22-10-2019
  • Mathematics
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What are the focus and directrix of the parabola that is the graph of the function f(x)=x²?

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nuuk nuuk
  • 22-10-2019

Answer:

Step-by-step explanation:

Given

[tex]y=x^2[/tex]

comparing it with standard equation [tex]x^2=4ay[/tex]

so 4a=1

[tex]a=\frac{1}{4} [/tex]

so Focus of parabola is (0,0)

directrix

y=-a

here [tex]a=\frac{1}{4}[/tex]

[tex]y=-\frac{1}{4}[/tex]      

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