castanmacy
castanmacy castanmacy
  • 21-06-2019
  • Mathematics
contestada

Factor completely 5y^2-2y-3

Respuesta :

freckledspots freckledspots
  • 21-06-2019

Answer:

(5y+3)(y-1)

Step-by-step explanation:

5y^2-2y-3

I don't know if you like trial factors or not... but we can try that way

notice we have 5y^2

that can be written as 5y * 1y

Notice at the end we have -3

that can be written as -3*1

So possible answers could be:

(5y-3)(1y+1)   =5y^2+5y-3y-3=5y^2+2y-3

So this was almost right.

If we just switch the signs the - and + there we will have got it

(5y+3)(1y-1)=5y^2-5y+3y-3=5y^2-2y-3 which is good

So the answer is (5y+3)(y-1)

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