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  • 24-05-2019
  • Mathematics
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if h (r)= 2/3 r - 6, what is the value of h(-9)?

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 24-05-2019

Answer:

[tex]h(-9)=-\frac{2}{33}[/tex]

Step-by-step explanation:

The given expression is [tex]h(r)=\frac{2}{3r-6}[/tex]

We want to find the value of h(-9).

We substitute r=-9 to obtain:

[tex]h(-9)=\frac{2}{3(-9)-6}[/tex]

We multiply out to obtain:

[tex]h(-9)=\frac{2}{-27-6}[/tex]

We simplify the denominator to obtain:

[tex]h(-9)=\frac{2}{-33}[/tex]

This is the same as:

[tex]h(-9)=-\frac{2}{33}[/tex]

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