Answer:
[tex]\large\boxed{x=-1.5\ or\ x=1}[/tex]
Step-by-step explanation:
The zeros of f(x) = 2x² + x - 3:
[tex]2x^2+x-3=0\\2x^2+3x-2x-3=0\\x(2x+3)-1(2x+3)=0\\(2x+3)(x-1)=0\iff2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\x=-1.5\\\\x-1=0\qquad\text{add 1 to both sides}\\x=1[/tex]
