[tex]\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})~\hspace{10em} slope = m\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=\cfrac{1}{3}[x-(-2)]\implies y+2=\cfrac{1}{3}(x+2)[/tex]
