Relax

Respuesta :

gmany

[tex]-\dfrac{1}{2}x > 4\qquad|\text{change the signs}\\\\\dfrac{1}{2}x < -4\qquad|\cdot2\\\\x < -8\to\{x|x\in\mathbb{R},\ x < -8\}\to\boxed{B.}[/tex]