nking18paqwbi nking18paqwbi
  • 23-06-2018
  • Mathematics
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the length of a rectangle is 2 more than its width. Find the perimeter
[tex]2l + 2w[/tex]
if its area is 15 ft^2

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hi8969
hi8969 hi8969
  • 23-06-2018
Area is length * width, so lw = 15
l = 2+w
so w(2+w) = 15 or w^2 +2w -15 = 0
Use quadratic formula to get (-2 +/- sqrt(4-4*1*-15))/2 or -5 and 3, but width cannot be negative, so 3 is the width. Plug into length, 3+2 = 5. Length is 5.
2*5 + 2*3 = 10+6 or 16 ft. 
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