The standard enthalpy change for the following reaction is -433 kJ at 298 K.

K(s) + 1/2 Cl₂(g) + 2 O₂(g) KClO₄(s) ΔH° = -433 kJ
What is the standard enthalpy change for the reaction at 298 K?

KClO₄(s) K(s) + 1/2 Cl₂(g) + 2 O₂(g)

_________kj