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The liquid air contains 200 g of liquid oxygen and 800 g of liquid nitrogen.
The specific heat capacity of liquid oxygen is 1.7J/(g °C) and the specific heat capacity of liquid nitrogen is 2.0J/(g °C).
Calculate the thermal energy needed to warm the liquid from -205°C to -196°C.
State the formula that you use in your calculation.

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Respuesta :

Answer:

17460 J

Explanation:

Q = m c  Δ T    is the formula to use  

 you have two masses and two different 'c' values to consider

Q =   200 g  (1.7 J/(g-C)( 205-196 C)   +  800 (2.0)(205-196)

Q = 17460 J

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