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25-09-2018
Mathematics

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solve L = a + (n - 1) d for d

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26-09-2018

[tex]a+(n-1)d=L\ \ \ \ |-a\\\\(n-1)d=L-a\ \ \ \ |:(n-1)\neq0\\\\\boxed{d=\dfrac{L-a}{n-1}}[/tex]

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